The Federal University of Agriculture Abeokuta is a very recreational school. The school was established in 1988 by the Federal government of Nigeria.  The school is also one of the best universities in Nigeria. 

Are you thinking or looking for how FUNAAB calculates their aggregate score? You are on the right page. We will give you full facts about FUNAAB aggregate or composite. 



Firstly, How Does FUNAAB Calculate its Aggregate Score for UTME/DE?

FUNAAB uses a Composite Grading System which assesses the O'Level, Post-UTME, and UTME/Transcript results of a candidate. The composite score is based on the ratio of 30:20:50 for the Post-UTME, O'Level result, and UTME scores respectively.


O'level points rely on ONLY five important subjects: English, Mathematics, Physics, Chemistry, and Biology. A1, B2, B3, C4, C5, and C6 grades are rated as 6, 5, 4, 3, 2, and 1 point respectively, all other grades carry 0 points. Thus, the maximum attainable Total O'Level points are thus 30points


NOTES

Where Agric is accepted for a pass in Biology, the grade of Agric does not indicate on the O'Level point.

Where a candidate submits 2 results, the calculation is based on the better grade for each of the important subjects. However, 1 point exists in the total score obtained.

O'Level composite percentage = Total O'Level Points multiplied by 2/3.


UTME/DE composite percentage


UTME: Total UTME Score divided by 8


DE: (Total Obtainable GP or Points / CGPA or Points obtained) * 0.3


Post-UTME composite percentage = Post-UTME score multiplied by 0.3


COMPOSITE = Sum of all three composite percentages. 

For Example: 

If a candidate has 240 in Jamb and his O level goes Like this: Maths-B3, Chemistry-C4, Biology- B2, English- C5, Physics-C6, Economic-B3, Geography-A1 and had 58% in the post utme. Then he can calculate his composite, by heeding the format below:


Jamb score divided by 8 i.e 240/8=30

For the O level, only 5 important subjects (math, English, chemistry, biology, and physics) are needed. There he has Math – B3 – 4 points, English – C5 – 2 points, Chemistry – C4 – 3 points, Biology – B2 – 5 points, Physics – C6 – 1 point Total gross points for O level= 4+2+3+5+1=15.  This score is then multiplied by 2/3 i.e 15 x 2/3=10. His post utme score is allocated 30% and is multiplied by

0.3. i.e 58 x 0.3=17.4


Therefore, the candidates’ composite is the accumulation of these three scores i.e Jamb+O’level+post utme. i.e 30+10+17.4=57.4 Hence, the candidate’s composite is 57.4. 


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